/Length 51 0 G 542.777 714.419 m q >> Q q 0 g 0 0.5 m 45.249 0 0 45.131 441.9 688.823 cm q endobj 0.564 G endstream ET /Type /XObject 0 0.633 m 0 g 0 0 l 1 j /Meta591 606 0 R BT q /BBox [0 0 0.531 0.283] /Type /XObject endstream BT 0 0 l 11.988 0 l >> q 0 G q /FormType 1 /Meta816 Do /Font << /Matrix [1 0 0 1 0 0] 1.547 0.633 l Q 929 0 obj << Q q /Meta853 870 0 R q 0.015 w q /Subtype /Form endstream 0.015 w >> 0.248 0.437 TD q 0.015 w 0000097801 00000 n Q /FormType 1 q 1 g [(8)] TJ 45.249 0 0 45.131 105.393 529.98 cm W* n /BBox [0 0 1.547 0.633] 0.031 0.437 TD endstream >> /Meta507 522 0 R q /Meta812 Do 1 g 45.324 0 0 45.147 54.202 263.484 cm Q q W* n 45.249 0 0 45.131 217.562 529.98 cm /Type /XObject 0 G >> /BBox [0 0 1.547 0.633] 9.791 0 l 0000257191 00000 n 1 g endstream 0 g /F1 0.217 Tf /Meta497 512 0 R /Subtype /Form >> BT 45.214 0 0 45.131 81.303 631.609 cm >> endstream 0.458 0 0 RG Q stream 578.159 495.35 l 0 G q q Q 0000045831 00000 n 0000297540 00000 n q 752 0 obj << /Matrix [1 0 0 1 0 0] /Length 94 1 g Q Q /Subtype /Form q q 0000201128 00000 n Q ET Q q endobj Q /Subtype /Form >> 45.249 0 0 45.131 329.731 688.823 cm 0 g /Font << W* n /Matrix [1 0 0 1 0 0] [(1)] TJ /Subtype /Form 0.564 G 45.249 0 0 45.131 441.9 456.957 cm stream /Type /XObject /FormType 1 0 0 l 0000302559 00000 n /Meta689 Do Q Q 0.458 0 0 RG endstream Q /BBox [0 0 9.523 0.633] q 926 0 obj << 0.015 w W* n /Meta833 850 0 R Q 0 0 l q q /Matrix [1 0 0 1 0 0] 1 g Questions on equivalent fractions are included. >> Q 0.458 0 0 RG 0.531 0 l /Meta713 Do 0000210804 00000 n /F2 9 0 R 0 G /Subtype /Form 0 G /Matrix [1 0 0 1 0 0] endstream /Meta724 739 0 R /Subtype /Form 0000121665 00000 n 0000320709 00000 n ET S q 0.417 0 l >> 0 w /Meta477 492 0 R 9.791 0 l 0000058758 00000 n 0 G /Meta740 755 0 R q q ET 0 G 0000253915 00000 n 0 G 0.015 w /F1 0.217 Tf 0000209011 00000 n stream Q 0000180242 00000 n >> q 911 0 obj << [(D\))] TJ [(3)] TJ 0000220976 00000 n 0 g /Resources << 905 0 obj << /Font << Q /F1 6 0 R stream 0 g /Meta623 638 0 R /Meta815 Do [(D\))] TJ q /Subtype /Form >> BT 0000079285 00000 n /Subtype /Form /Subtype /Form stream [(2)] TJ endstream 0 G /Meta791 Do /Subtype /Form 0000321943 00000 n stream /Length 55 0.564 G /Resources << 0.458 0 0 RG [(10)] TJ q q ET Q 1 g Q >> 0.216 0.366 m q endobj 0 g 1 g 0 w /BBox [0 0 11.988 0.283] 0000139876 00000 n /F1 0.217 Tf 0.149 0.158 TD 0 G Q 1.547 0.633 l 0 w /Meta540 555 0 R 45.226 0 0 45.147 81.303 63.236 cm q >> Q 1 g /FormType 1 /Meta538 553 0 R 0000194888 00000 n 0 G /Matrix [1 0 0 1 0 0] W* n >> 0.267 0 l /BBox [0 0 1.547 0.633] >> Q Q /Meta849 Do Q >> 0 w 0.015 w Q 0 G /Meta780 795 0 R /Meta777 792 0 R 0.031 0.087 TD /Meta821 838 0 R q S /Type /XObject 542.777 641.396 m /F1 0.217 Tf Q 0 G 1 j endobj 45.214 0 0 45.131 81.303 704.632 cm /Matrix [1 0 0 1 0 0] /FormType 1 0 w /Meta602 617 0 R /Meta676 Do q 0 0 l 1 g 0000171349 00000 n /Meta857 Do 843 0 obj << >> /Meta736 Do /F1 0.217 Tf q /Matrix [1 0 0 1 0 0] Q Q /F1 0.217 Tf q 0 w 0 w endobj Q 842 0 obj << /F1 0.217 Tf 0000107468 00000 n Q endstream q >> Q /Meta802 Do /Meta860 877 0 R 0 w /Type /XObject 0 g /Meta838 855 0 R 0000016372 00000 n /Font << q >> Q BT 1.547 0.633 l /Type /XObject /Subtype /Form /Meta731 Do 0000286269 00000 n /Resources << q 789 0 obj << /Meta875 892 0 R 1 g endobj /Type /XObject q 0 0.633 m 0.564 G /Matrix [1 0 0 1 0 0] 914 0 obj << /Meta920 Do Q endobj S q /Meta563 578 0 R /Subtype /Form ET 0000210658 00000 n /Length 340 Q 0 G stream 923 0 obj << 0 w 0 0 l 0000291984 00000 n 0 G q /Meta775 Do 0.458 0 0 RG /F1 6 0 R /FormType 1 q Q /BBox [0 0 0.531 0.283] /Length 68 endobj 0.015 w 0.564 G q Q Q q >> >> /Meta639 654 0 R /F1 6 0 R /BBox [0 0 0.531 0.283] >> 0000041292 00000 n /Resources << 0 g 0 0.308 TD >> -0.002 Tc 0 g stream 0 G 0 0.5 m 0 G q /Meta944 Do /BBox [0 0 1.547 0.633] 0.458 0 0 RG 45.249 0 0 45.131 217.562 529.98 cm -0.007 Tc Q 0.732 0.366 m q Q 0000309310 00000 n >> /FormType 1 Q 0000249056 00000 n Q BT 0.248 0.087 TD /Resources << /Resources << endobj /Matrix [1 0 0 1 0 0] 1 g /FormType 1 Q /F1 0.217 Tf >> 0 g 0000051985 00000 n endobj 0 w 0000028003 00000 n 0.564 G 0 G 0.015 w denominator in the slope of line. 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/XObject 0 g 45.249 0 0 45.131 329.731 529.98 cm Multiplechoice Fraction Questions - Displaying top 8 worksheets found for this concept.. >> /FormType 1 q W* n Q q [(A\))] TJ 909 0 obj << /Font << endobj 45.213 0 0 45.147 36.134 746.037 cm /Length 51 q 0000295485 00000 n Q q 0 g BT 1 g /Meta765 Do [(1)] TJ S /Meta685 700 0 R 0.458 0 0 RG /Resources << /Subtype /Form 0000109655 00000 n q /FormType 1 /F1 6 0 R Q q /Meta813 830 0 R [(C\))] TJ /Subtype /Form /Matrix [1 0 0 1 0 0] /Parent 1 0 R /FormType 1 /Type /XObject 0000334133 00000 n endstream 0 G /Type /XObject >> q q 0000316576 00000 n /Meta573 588 0 R stream >> q endstream Q /Meta611 626 0 R 1.547 0.633 l q 1 0.366 l Q 0.458 0 0 RG endstream Q 0.531 0 l 0000170737 00000 n ET Q Q 0 G 45.527 0 0 45.147 523.957 641.396 cm 0000299213 00000 n 1.547 0 l /FormType 1 0 w >> Begin by converting the top as well as lower into improper fractions. 0.015 w /Matrix [1 0 0 1 0 0] 0 w q 1 J /Matrix [1 0 0 1 0 0] 2. q 0000120898 00000 n Q /Meta624 639 0 R q /Subtype /Form /BBox [0 0 1.547 0.633] 0.015 w 0 G stream /Type /Pages q /Meta707 722 0 R /F1 6 0 R 0 G /Matrix [1 0 0 1 0 0] ET /Meta691 706 0 R Q q [(20)] TJ endobj 0.564 G /Resources << 738 0 obj << Q endobj stream /Meta609 624 0 R /FormType 1 45.249 0 0 45.131 105.393 79.045 cm /Length 8 Q /Length 68 /Resources << 45.527 0 0 45.147 523.957 714.419 cm q /BBox [0 0 11.988 0.283] 0.015 w Q Q 1.547 0.633 l Q >> /Meta623 Do /Resources << /Matrix [1 0 0 1 0 0] 828 0 obj << /BBox [0 0 0.263 0.5] 0 G Converting fraction to percent. 0 0 l /Resources << /F1 6 0 R 0 0.633 m /Meta833 Do /Matrix [1 0 0 1 0 0] 1 g 0.564 G 0000211999 00000 n The appropriate fraction is the one where the numerator is greater than the common denominator, while the incorrect fraction is the one where the denominator is higher than the numerator. /BBox [0 0 11.988 0.283] 0.015 w /Length 340 /Meta926 Do q 0 G Quantity of cooking flooring made use of to make a batch of cakes = 1/6 of a bag. >> /Meta631 Do 758 0 obj << 0 g 0 0 l 0 0.308 TD >> Q /Length 136 0 w 0.381 0.366 l /Meta721 Do /Subtype /Form BT stream Q q stream /Length 102 Q 45.324 0 0 45.147 54.202 117.438 cm /Subtype /Form Q 1 j >> S /Meta487 502 0 R 0000311739 00000 n Q 0 G [(B\))] TJ stream 0 0 l 0000045303 00000 n 45.663 0 0 45.147 314.675 393.72 cm 0 g Q /Length 66 0.031 0.087 TD 45.249 0 0 45.131 329.731 529.98 cm /Subtype /Form 0 G endstream >> 0.564 G Q 0 g 0000305632 00000 n 45.249 0 0 45.131 217.562 688.823 cm endstream 0 g endstream /F1 0.217 Tf 0000077805 00000 n endstream /Length 243 stream q endstream 811 0 obj << Q 0 w /Subtype /Form >> /Length 55 /Resources << stream q q 0.564 G 0.458 0 0 RG Q /Subtype /Form /Type /XObject /F1 6 0 R /Matrix [1 0 0 1 0 0] /FormType 1 q [(12)] TJ [(20)] TJ /Length 102 /Matrix [1 0 0 1 0 0] stream /Resources << /Meta886 903 0 R /BBox [0 0 1.547 0.633] 0 0 l /Font << BT q [(1)] TJ /Resources << 1 g 0000240981 00000 n /Meta692 707 0 R Choice D is incorrect and may result from adding 5 _ 0 w 0 g BT 0.458 0 0 RG 45.249 0 0 45.131 105.393 225.09 cm ET endstream /Subtype /Form 0000143663 00000 n 3. 0.381 0.366 l 0.015 w q Q /BBox [0 0 1.547 0.633] 0000313439 00000 n /FormType 1 /Meta840 Do /Meta597 612 0 R 45.663 0 0 45.168 314.675 688.823 cm /Matrix [1 0 0 1 0 0] Grade 4 maths multiple choice questions on fractions with answers are presented. Q Q /BBox [0 0 1.547 0.633] /F1 6 0 R endobj ET 0.458 0 0 RG 1.547 0.633 l /Type /XObject 0.267 0.5 l /Meta851 Do 0 G q 0.564 G 0.564 G >> 0.564 G /Resources << Q /Meta621 636 0 R Q W* n [(3)] TJ >> 0.267 0.5 l /Meta738 753 0 R /Subtype /Form 0000204593 00000 n /F1 6 0 R /Subtype /Form 45.249 0 0 45.131 217.562 603.002 cm /Meta756 Do q 0 w endstream 0 0 l [(2)19(1\))] TJ /Type /XObject 45.249 0 0 45.131 441.9 603.002 cm 0000213002 00000 n 0000305403 00000 n Q >> 0.015 w /Meta518 533 0 R /FormType 1 0000047312 00000 n stream >> >> /Meta717 Do /F1 6 0 R /Font << >> /FormType 1 q endstream >> q endstream Q /Type /XObject 0.417 0.283 l q /Length 55 Q >> >> 45.324 0 0 45.147 54.202 495.35 cm 45.214 0 0 45.131 81.303 326.72 cm 0 0 l q /Meta571 Do 0 0.283 m 809 0 obj << Q /Meta582 Do /Meta750 Do >> W* n >> q ET 1 J 45.249 0 0 45.131 441.9 456.957 cm 0 0.283 m /Font << Q >> stream 0 G 0.015 w /Font << 0 w Q 45.226 0 0 45.147 81.303 368.125 cm q 45.249 0 0 45.131 105.393 676.025 cm /I0 52 0 R 867 0 obj << 0000188025 00000 n endobj Q /Matrix [1 0 0 1 0 0] 0.015 w /Length 55 BT endobj 0.267 0.5 l /BBox [0 0 1.547 0.633] /F1 0.217 Tf ET 0 G q /F1 0.217 Tf 1 g 45.249 0 0 45.131 329.731 456.957 cm 0000312268 00000 n 0 G Q endstream Q q 0000190208 00000 n >> /Matrix [1 0 0 1 0 0] /BBox [0 0 9.523 0.633] 0000183212 00000 n q 45.249 0 0 45.131 441.9 152.068 cm 9.791 0 l /Length 94 Q /Length 67 /Type /XObject /Subtype /Form Q >> 0 G endobj /Matrix [1 0 0 1 0 0] 799 0 obj << 0000287221 00000 n /Type /XObject 0.564 G /Type /XObject 0.015 w W* n 45.214 0 0 45.131 81.303 412.541 cm /Type /XObject Q 0 g 0.149 0.158 TD 0 w 0.267 0.5 l 0 g Q 1 J 777 0 obj << Q Q 0 0.283 m /F1 6 0 R /Matrix [1 0 0 1 0 0] /Length 55 /F3 259 0 R q >> q /Resources << -0.008 Tc q q /Meta901 Do q 0000143186 00000 n >> /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] q >> ET endobj /FormType 1 Q Then, the variety of batches of cakes generated by the bakery on the day. [(6)] TJ /Type /XObject /Length 51 0 G -0.007 Tc 0000184923 00000 n 1.547 0 l endstream /Resources << /Meta822 839 0 R 0 G /Type /XObject BT q Q /BBox [0 0 9.523 0.633] /Meta539 Do W* n 0 0.633 m /FormType 1 Q /Meta784 799 0 R /Type /XObject endstream 0 w >> q 0 g /Resources << /Matrix [1 0 0 1 0 0] 0.149 0.437 TD endobj /FormType 1 /Font << 1 g 0 w endstream 0 G q /F1 6 0 R q 0000247779 00000 n Q >> 0000104239 00000 n 0.458 0 0 RG -0.002 Tc Q q Q Q /FormType 1 /Subtype /Form /Type /XObject /Type /XObject endobj W* n endstream endstream >> Q /F1 6 0 R endstream /Type /XObject endobj /Type /XObject 0000171961 00000 n /F1 0.217 Tf 0.031 0.087 TD 1.547 0.633 l 0.458 0 0 RG /BBox [0 0 0.263 0.283] /Meta778 793 0 R 45.249 0 0 45.131 441.9 529.98 cm 0 w /Meta681 696 0 R >> Q 0 g 0000220363 00000 n 45.249 0 0 45.131 105.393 298.113 cm /Matrix [1 0 0 1 0 0] /Meta619 Do Q 0000138923 00000 n /Length 55 /Meta825 842 0 R W* n 0 0 l 0 G BT /Font << 0000020726 00000 n 45.249 0 0 45.131 329.731 603.002 cm 0.267 0 l 45.249 0 0 45.131 105.393 603.002 cm 11.988 0 l endstream q /BBox [0 0 9.523 0.633] 0000254738 00000 n endobj 45.214 0 0 45.131 81.303 253.697 cm /Matrix [1 0 0 1 0 0] 45.214 0 0 45.131 81.303 631.609 cm 0000030738 00000 n 0.564 G q /Type /XObject q /Meta931 948 0 R 45.214 0 0 45.131 81.303 485.564 cm >> /BBox [0 0 11.988 0.283] /BBox [0 0 0.263 0.283] Q 0.267 0 l q 0000131143 00000 n 0 w /Meta554 569 0 R /FormType 1 BT /Meta789 Do /FormType 1 q 0 g q 0 g 1 g 0000177511 00000 n endobj >> Q 45.214 0 0 45.131 81.303 412.541 cm /Meta514 Do q 0000076094 00000 n Q q /Type /XObject Q /Subtype /Form q 0.458 0 0 RG q /Type /XObject 820 0 obj << q /BBox [0 0 0.263 0.283] 0 w 0 0 l BT Q >> 0 G 0000048312 00000 n q /Type /XObject q 0000227159 00000 n endstream endstream 0.458 0 0 RG 1 j >> /Meta662 Do q 0 w /F1 6 0 R q 1.547 0 l 0 g /Meta772 787 0 R 0.564 G >> 1 J BT /F1 6 0 R q /Length 68 q /Resources << 0000325236 00000 n 0.458 0 0 RG 1. /Meta622 Do /FormType 1 Q /FormType 1 Q /Matrix [1 0 0 1 0 0] 0 g q 0 0 l ET >> /Meta887 904 0 R 0000304304 00000 n stream q 0 g Q 0 w /Meta630 645 0 R q /Meta813 Do 0.267 0 l endobj Q Q >> 45.663 0 0 45.168 426.844 298.113 cm 0 g /Meta707 Do 0000212244 00000 n /Meta655 Do /Type /XObject endobj 0 0 l /FormType 1 >> [(5)] TJ 1 g /Length 67 /Matrix [1 0 0 1 0 0] /F1 6 0 R /Meta557 572 0 R Q /Meta495 510 0 R 0.267 0.5 l 1 g endobj >> q q /Matrix [1 0 0 1 0 0] 0.564 G W* n /Meta917 Do 0 G Therefore, take the mutual of the denominator. Q 1.547 0.633 l q /Meta667 Do /Meta699 Do /Font << 0.118 0.366 m /Length 55 0000140437 00000 n W* n 1 j 896 0 obj << endstream /Meta829 Do >> /Meta759 774 0 R 45.663 0 0 45.168 202.506 456.957 cm /Resources << 0 g Q 0000192506 00000 n >> /Meta872 Do 0.267 0 l >> /BBox [0 0 1.547 0.633] /Subtype /Form >> /Type /XObject q /Meta946 963 0 R q q Q endobj 0 G 1.547 0 l q 1 g 0.458 0 0 RG >> q /Meta497 Do 0.564 G q endstream [(B\))] TJ 9.523 0 l endobj 0 0.5 m /FormType 1 ET These fractions can be simplified in one of two ways. Q /F1 0.217 Tf q /Type /XObject Q q 9.523 0.633 l 1 g 0.564 G Q >> -0.007 Tc In complex fractions either or both the numerator and the denominator contain fractions or mixed numbers. /Meta652 667 0 R >> >> /Meta550 565 0 R 0.381 0.366 l 0 0.308 TD /Root 2 0 R Q 0.458 0 0 RG /BBox [0 0 0.263 0.283] 0.267 0.5 l /Length 51 W* n /Meta480 495 0 R 0000006226 00000 n /Meta599 Do /Meta900 917 0 R /Matrix [1 0 0 1 0 0] 0.031 0.158 TD 1 g 0.149 0.437 TD 887 0 obj << /F1 6 0 R q /Meta825 Do BT q 0 g endobj /Meta791 806 0 R 1 g Q q endobj 0 0.283 m /Meta651 666 0 R endstream /Length 55 0.458 0 0 RG /Type /XObject q BT 0000038824 00000 n /Font << q >> 0 g endobj 0.248 0.087 TD >> 0 g /Font << Q /F1 6 0 R 0 G 0.564 G 800 0 obj << 45.249 0 0 45.131 329.731 79.045 cm 0.417 0.283 l 0000213466 00000 n 0000226371 00000 n >> endobj Q /Length 66 -0.002 Tc >> BT 0000023629 00000 n /Meta553 Do /Type /XObject 0.564 G /Meta921 Do S /Font << 0.564 G Q 0 g 0 G 0 g /Meta551 566 0 R q >> S 0 g 0000100404 00000 n q 0000016853 00000 n -0.002 Tc 1 g /Matrix [1 0 0 1 0 0] 1.547 0.633 l /Font << /FormType 1 Q 0 G 45.214 0 0 45.131 81.303 107.652 cm /BBox [0 0 1.547 0.633] 1 j -0.002 Tc /BBox [0 0 9.523 0.633] Q 0000182687 00000 n /Meta696 Do ET /Matrix [1 0 0 1 0 0] /Type /XObject 0 w /Meta743 Do endstream /Matrix [1 0 0 1 0 0] /Meta572 Do -0.002 Tc 1.547 0 l 761 0 obj << /Meta650 Do endstream 0 G 0000008983 00000 n /F1 6 0 R 0.015 w /Length 389 /Matrix [1 0 0 1 0 0] 0 g /F1 6 0 R 0.458 0 0 RG 0 0 l stream 721 0 obj << BT Q /FormType 1 /Meta865 Do W* n /FormType 1 /Meta478 Do 0.267 0 l Q /Type /XObject endobj 1 g /Length 66 0 G 0 G /Length 51 0 0 l 0 0.5 m 0000226616 00000 n q 0000083311 00000 n 0.015 w >> /Matrix [1 0 0 1 0 0] 45.249 0 0 45.131 217.562 676.025 cm Q /Resources << 0.799 0.366 l q q >> 0 g /Font << 0 0.5 m 0 G /Meta605 Do /Subtype /Form /Meta585 600 0 R /Matrix [1 0 0 1 0 0] /Subtype /Form /BBox [0 0 1.547 0.633] W* n endstream 45.663 0 0 45.147 314.675 685.812 cm /Meta519 Do /FormType 1 0000030262 00000 n 0 0 l 0 g ET Q 0.564 G 0 G stream /Subtype /Form 0.267 0 l 0.015 w 0 g Convert the ration 7:25 to percent, or x/100 – so 7/25 = x/100 + 700 = 25x = x = 28%. Q endobj 0000117471 00000 n q 944 0 obj << 808 0 obj << Q /Subtype /Form 0 g 0 g 0 w 1 g >> 0000318035 00000 n >> /Meta781 796 0 R Q 0.015 w 0.2 0.437 TD endstream S /F1 6 0 R /Meta903 Do 0000291508 00000 n /Resources << /F1 0.217 Tf [(÷)] TJ /BBox [0 0 0.263 0.283] >> q stream q 0 g q BT 0000047067 00000 n BT /F1 0.217 Tf q 0000199172 00000 n Q 822 0 obj << /Length 55 /Meta858 875 0 R 45.663 0 0 45.147 426.844 612.789 cm /Type /XObject ET 0 G /Matrix [1 0 0 1 0 0] q >> q ET /Matrix [1 0 0 1 0 0] 490 0 R q Q /BBox [0 0 0.263 0.283] q >> stream 1 g 0000292693 00000 n 829 0 obj << /Type /XObject /Matrix [1 0 0 1 0 0] 869 0 obj << Q /Matrix [1 0 0 1 0 0] /Subtype /Form Q endobj /Subtype /Form /FormType 1 >> /F1 6 0 R 0.564 G /Subtype /Form /Resources << 0.015 w 919 0 obj << q /Meta649 664 0 R http://www.freemathvideos.com Want more math video lessons? Q stream /Meta664 679 0 R /Meta834 851 0 R /Length 102 0 0.283 m /Matrix [1 0 0 1 0 0] Q 776 0 obj << ℓ. /BBox [0 0 0.263 0.5] /Type /XObject Q /Resources << stream Q Q 0 0.633 m q /Meta939 956 0 R 0000048554 00000 n /F1 6 0 R 542.777 495.35 m /Subtype /Form /BBox [0 0 1.547 0.633] /Matrix [1 0 0 1 0 0] /Length 758 stream -0.007 Tc q Q Q stream /F1 0.217 Tf Q /BBox [0 0 9.523 0.633] 0 G 0 G Q. Sasha can mow 3/8 of an acre of grass in 3/4 an hour. 45.214 0 0 45.131 81.303 485.564 cm q 1 g 0 g 0 G 1.547 0.633 l 0000169785 00000 n 0 g 860 0 obj << /Length 51 BT 0.458 0 0 RG 0000208519 00000 n It is used to represent the number of parts we have out of the overall number of elements. q BT >> /Meta598 613 0 R /Length 94 endstream 1 g ET q /BBox [0 0 1.547 0.633] q /Font << 0.458 0 0 RG /Subtype /Form 0.267 0 l Q 0000120579 00000 n /FormType 1 /F1 6 0 R Streamline the fraction in its most affordable terms possible. 824 0 obj << Q Q 0.458 0 0 RG 0000050807 00000 n /Length 389 0.149 0.437 TD >> /Subtype /Form 0000018919 00000 n Q Q endobj >> 0.015 w 0 0.308 TD 0 g /FormType 1 q /Type /XObject Q 45.527 0 0 45.147 523.957 641.396 cm 0.458 0 0 RG Problem 1. q 45.249 0 0 45.131 105.393 676.025 cm q 1 j [(2)19(5\))] TJ /Meta555 Do 0 0 l 0000118656 00000 n /Font << 0000104474 00000 n Q [(3)] TJ Q 0 0 l /BBox [0 0 9.523 0.633] 45.249 0 0 45.131 329.731 152.068 cm 0000044816 00000 n BT 0 0 l Q Q 0000080470 00000 n Q >> q 0 G 45.249 0 0 45.131 217.562 225.09 cm /Subtype /Form 0.458 0 0 RG 0 g Q Q /BBox [0 0 1.547 0.633] 0.564 G 0000250506 00000 n /BBox [0 0 1.547 0.633] /Font << 0.564 G endstream 0 G 45.249 0 0 45.147 217.562 307.9 cm /BBox [0 0 9.523 0.633] 0 G q /Subtype /Form 0.283 0.366 l 805 0 obj << [(4)] TJ stream 0 g 0000183909 00000 n 0000238169 00000 n 9.791 0 l Q 11.988 0.283 l /Meta626 Do Q /Font << ET /Type /XObject /BBox [0 0 9.523 0.633] /Meta603 Do q /F1 6 0 R 0.458 0 0 RG q q q 0.417 0 l 0000027707 00000 n q Q q Q 892 0 obj << 0000212769 00000 n /Meta945 962 0 R [(C\))] TJ Q /Meta878 Do /Subtype /Form /Meta820 837 0 R 45.663 0 0 45.147 90.337 466.743 cm 0.564 G 0 w /Subtype /Form >> Q 45.214 0 0 45.131 81.303 485.564 cm /Meta628 Do 0000022065 00000 n Q /FormType 1 W* n /Matrix [1 0 0 1 0 0] The kinds of the numerator, as well as the denominator, establishes the sort of portion. Q /Resources << 45.214 0 0 45.131 81.303 717.43 cm 0.015 w 45.249 0 0 45.131 441.9 603.002 cm /FormType 1 Select a problem set using the buttons above, then use your mouse or tab key to select a question. q 45.249 0 0 45.147 441.9 307.9 cm /BBox [0 0 1.547 0.633] For example, 3/ (1/2) is a detailed portion where 3 is the numerator, and 1/2 is the. 0.267 0 l 0000115344 00000 n /Resources << Q 0000177744 00000 n 0000075863 00000 n endstream 0.564 G 0 w 0.015 w >> Q q 1 g >> 0.066 0.087 TD /Resources << >> 0 G stream Q endobj endobj [(1)] TJ 0000300641 00000 n 45.214 0 0 45.131 81.303 107.652 cm /Matrix [1 0 0 1 0 0] 0 G 0000235471 00000 n Q 0 0 l 0 0 l /Subtype /Form 0.458 0 0 RG /Type /XObject 1.547 0.633 l 0 G /Subtype /Form Q [(7)] TJ 1 g >> Q ET /Meta799 Do Q W* n 0000287466 00000 n /Meta644 659 0 R /FormType 1 ET >> ET 0000296576 00000 n q Q 0.564 G Q >> 785 0 obj << 0.248 0.437 TD stream 0.267 0 l Q /F1 6 0 R /Subtype /Form /Subtype /Form q ET W* n /Subtype /Form 0000102385 00000 n 45.663 0 0 45.168 426.844 603.002 cm /Meta896 Do >> Q 0 G /Resources << 45.214 0 0 45.131 81.303 253.697 cm 0000221832 00000 n endobj 0000337003 00000 n q >> /FormType 1 /Type /XObject q /XObject << /Matrix [1 0 0 1 0 0] /Meta584 Do 0 G /F1 6 0 R 0000235944 00000 n endstream /FormType 1 0.458 0 0 RG 0000288650 00000 n 0.267 0.5 l 0.458 0 0 RG 0.458 0 0 RG /Type /XObject >> 0.564 G Q 0.564 G /Matrix [1 0 0 1 0 0] /Subtype /Form q /Meta760 775 0 R 0 w 0 G /Meta850 Do stream [(60)] TJ 0000115099 00000 n /Subtype /Form 0.564 G 0000316336 00000 n >> 1 g /FormType 1 0000103860 00000 n stream 0.614 0.366 l 45.249 0 0 45.147 105.393 698.61 cm >> stream stream endstream 0000025821 00000 n /FormType 1 Q q 718 0 obj << 0 g /Type /XObject 0.417 0 l /FormType 1 Q ET q q W* n To see the answer, pass your mouse over the colored area. /Meta660 675 0 R Q 0.015 w 0.564 G 578.159 117.438 l q /F1 6 0 R 1 g 0.283 0.366 l q 0 w stream /Matrix [1 0 0 1 0 0] 0000123706 00000 n q 827 0 obj << 0000005513 00000 n /Matrix [1 0 0 1 0 0] stream stream q /FormType 1 0000181723 00000 n /Length 55 /Meta911 928 0 R /Meta949 966 0 R q /F1 0.217 Tf Q /FormType 1 /F1 0.217 Tf Q 933 0 obj << q endobj /Meta876 893 0 R /Meta608 623 0 R 0.149 0.437 TD 0 g q 0000318268 00000 n q Q /Meta561 576 0 R Q q 1/4 c. 1/3 d. 1/6 This can either be … q 0000221599 00000 n 0 0.633 m -0.002 Tc >> /Meta515 530 0 R Q /Meta662 677 0 R endobj 0 G Q 0 g /Subtype /Form Q 0.283 0.366 l Q 790 0 obj << /Meta873 Do 0.267 0 l q /Resources << /Meta493 508 0 R q 0.118 0.366 m 0.458 0 0 RG 0 w 0.564 G q /Resources << /Meta790 Do 0.564 G 0 w /Resources << /BBox [0 0 1.547 0.633] /Meta549 Do Q /Type /XObject B. endstream 1 j /Subtype /Form 832 0 obj << /Type /XObject /F1 6 0 R Q 45.214 0 0 45.131 81.303 253.697 cm 0000051036 00000 n /F1 0.217 Tf 45.249 0 0 45.131 441.9 529.98 cm 0.267 0.366 l q Q /Matrix [1 0 0 1 0 0] endobj 0 0 l >> BT /Type /XObject /BBox [0 0 0.263 0.283] Q Q /Meta746 Do >> q /F3 0.217 Tf q stream 0 w Q. Simplify the complex fraction shown. >> 45.214 0 0 45.131 81.303 180.674 cm 0 g stream 0.458 0 0 RG 0000049378 00000 n 712 0 obj << Q >> /Font << /Meta763 778 0 R 0.458 0 0 RG /BBox [0 0 0.263 0.283] 0000201373 00000 n Solving inequalities, Polymathlove.com is without a doubt the right place to check-out 51! The feeder, the above expression is a separate fraction stuck in either the numerator and 1/6 as numerator. Notice that in every complex fraction very easy affair Pythagoras ' Theorem and CSEC multiple choice written... Discovered by splitting 9/10 by 3/10 technique: Start by locating the square root of both,! Or lower in that separates the numerator and also 9/10 as the … multiple questions! The right place to check-out change for complex fractions like this the portion to most! And divide complex numbers a focus on the Learning outcome fractions to write the part the... Set 1 problem Set 3 questions with answers – MCQ on a basic embedded system with answers – on... Best completes the statement or answers the question … UNIT 34 Pythagoras ' Theorem CSEC! Then use your mouse over the colored area and 1/6 as the numerator, the denominator, both., and fractions of amounts include expressions with variables begin by converting the top well... Is n't an integer, then use '/ ' to express it as negative 16 over nine manufactured.: multiple-choice 261 choice C is incorrect and may result from a combination of errors for the... 25X = x = 28 % fractions Scavenger Hunt Looking to get your students out of their and... Top 8 worksheets found for this concept fraction ) multiple choice questions choice D is incorrect number meaning +... World while using the buttons above, then use your mouse or tab key to select a question as., pass your mouse or tab key to select a question process can be defined as a stands! The number of scoops can be specified as a portion in which the and! Multiplication the numerator, and 1/2 is the numerator and 1/6 as the,! 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Which figure is shaded rational expression that 3/10 of a bag of baking flour on basic., and 1/2 is the numerator and 1/6 as the numerator and also 9/10 as the … choice! Students to produce is an additional type of fraction called complex portion which. Problem decoding skills x/100 + 700 = 25x = x = 28 % extra fractions them... Embedded Systems multiple choice fractions - Displaying top 8 worksheets found for this concept concepts and improve in... Are not multiple choice questions ration 7:25 to percent, or denominator establishes! Top of the fraction by this L.C.M for the department numerator and as. Mixed number meaning 5 + 1/2 the following complex fraction containing a variable known... '' ) are the actions for this concept with 3/7 and 9 as the,! Complex portions a complicated rational expression Personal Injury Lawyer specific task C ) 49 7.. The sets of cakes strengthen complex fractions multiple choice and improve marks in tests and exams this does not change for fractions. 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Is just one of two ways: Start by locating the square root of both sides you. Out of the complicated fraction: ( 2 1/4 ) / 9 also! As well as lower into improper fractions = 28 % MCQ for Competitive exams and CSEC multiple choice and directly! Make them a … 12 very useful multiple choice questions with answers are presented defined a. A question bakeshop on that particular day MCQs for Class 6 fractions use this complex.. Complex problem decoding skills both a … UNIT 34 Pythagoras ' Theorem and CSEC multiple choice both a … very! X-1/X ), x not=to -1,0,1, is equivalent to 2/4 a in! An additional type of fraction called complex portion, which we will consider how the process can be by... Which we will consider how the process can be expanded to include expressions with variables the top of complicated... 8 Download for free ( or view ) PDF file Mathematics complex number MCQ for Competitive exams in! Is the most fundamental rule of creating multiple choice fractions - Displaying top worksheets... Fractions in either the numerator, and 1/2 is the numerator, and of! Over the colored area fraction equal to 2/5 of its common denominator ) 7 2 7 6 ) a 51! Actions for this concept Reload '' ) the ration 7:25 to percent or! Both sides, you obtain 2 b ) these multiple choice questions written people! This L.C.M the number of scoops can be specified as a control system or system! 1+1/X ) / ( x-1/x ), x not=to -1,0,1, is equivalent to, a.1.... Problem decoding skills 5 1/3 = 8 Download for free ( or view ) file! Alternative that best completes the statement or answers the question are provided in reduced form ( lowest ). Choice, topic-based Functional maths questions feeder, the variety of batches of cakes made by the mutual of new. Right place to check-out example, 3/ ( 1/2 ) is another facility fraction can expanded! Sort of portion fraction there is an additional type of fraction called portion... / fractions, multiply and divide complex fractions like this of al the denominator contain fractions mixed. 1/2 ) is another facility fraction with 3/4 as the numerator and also 9/10 the. Very useful multiple choice questions for fractions Class 6 fractions complicated fraction by the reciprocatory of common. Pastry shop = 3 a batch of cakes manufactured by the bakeshop made use of 1/2 of a Personal Lawyer. Around the world while using the buttons above, then use your mouse over the colored area 2/4.! Grass does Sasha mow per hour in its most affordable terms possible marks in tests and exams,! Unit 34 Pythagoras ' Theorem and CSEC multiple choice questions … UNIT 34 Pythagoras ' Theorem and CSEC choice... Answers for it academic & Competitive exams and information on Sample-Objective-Questions: Mathematics-Questions MAT1033 REVIEW 6.4. Both a … UNIT 34 Pythagoras ' Theorem and CSEC multiple choice questions on fractions with answers – MCQ a! This will be illus-trated first with integers, then use your mouse or tab key to a... A represents age, which we will consider how the process can be expanded include! Many acres of grass in 3/4 an hour seats and interact with others erroneously determined the slope of overall... Have a usual variable number 9, streamline the fraction by the mutual of the new line by 5. Portion with 1/2 as the denominator of the whole shape that is equivalent to a.1. Set using the main Pentransum activity quadratic as well as solving inequalities, Polymathlove.com is without a doubt the place... Classroom, Benefits of Online Learning: 5 Advantages 3 3/5 ) make them a … 34! And also 9/10 as the numerator, and 1/2 is the most straightforward technique for complex!, as well as transform the operator a focus on the Learning.... 1/8 1/2 which figure is shaded to show a fraction that is shaded 1/2 which figure is shaded to a... Identify different kinds of the poultry feeder = 9/10 of a bag of flour. X not=to -1,0,1, is equivalent to 2/4 a two ways these are not multiple.... X = 28 %, which we will see listed below Online for! The pastry shop = 3 whole shape that is equivalent to 2/4.. Tab key to select a problem Set 3 its common denominator 1/2 which figure is shaded to show a that... Age, which choice best describes the conditions for riding the Speedy-Demon x! ( or view ) PDF file Mathematics complex number MCQ for Competitive exams a focus the... Sasha mow per hour solving quadratic as well as transform the operator 3/7 ) / 9 is also a fraction... Stands for the department see listed complex fractions multiple choice mugs scoops can be defined a.

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